Fast question about a packet

[option]

Yeah I got that, I was strictly referring to strings you insert as DWORDs. Thanks for the clarification though

[brew]

No, not at all. Did you notice how I used single quotes? I put in a DWORD, not a string.
For example...
' ' is the same as putting in 0x20
'0' is the same as putting in 0x30
'!' is the same as putting in 0x21
'IX86' is the same as putting in 0x49583836.
Do you see?
So when you do something like... i = strchr(asdf, '0');, you're passing 0x30 as the second parameter. Notice how it asks for an int, not a string
Same thing with assigning a value to a byte...
Say you want to cut off the \n from a string after you called fgets().
I would do something like so:

Code Select Expand


asdf[strlen(asdf) - 1] = 0;

However, that's just my coding style. Others might have made the 0 instead '\0'. That doesn't matter, since they're the same.


Also, your myPacket.insertDWORD("whateverNTstringyouneedtosend"); wouldn't work at all. I assume insertDWORD takes an unsigned long (hence insertdword), not a string pointer. Putting that code in would result in an error. For inserting NT strings, you should check out mypacket.insertNTString.

EDIT* Whoops, didnt see mynd's post.

[option]

Alright, so just for my reference, this is what I just did - just to see if I was on the same page as you guys.

putting 'IX86' into an unsigned long int, is the same as putting in 0x49583836, which I understand.

Code Select Expand

#include <iostream>

const unsigned long int IX86 = 'IX86';

using namespace std;

int main () {
cout << IX86 << endl;

return 0;
}

My program returns 1230518326.

That isn't IX86 the string in ASCII, HEX, or octal. What is it?

[Barabajagal]

Convert 1230518326 to hexadecimal and you get 0x49583836

[FrostWraith]

If you used a little C, (I dont know much about iostream), you could output it like this:

Code Select Expand

#include <stdio.h>

const unsigned long int IX86 = 'IX86';


int main (void)
{
printf("%X\n", IX86);

return 0;
}

[option]

Convert 1230518326 to hexadecimal and you get 0x49583836

Do I need to do that before I send the packet?

[Hdx]

Convert 1230518326 to hexadecimal and you get 0x49583836

Do I need to do that before I send the packet?

he was just stating a fact.
90% of the time when you're talking about data you put it in hex, unless its <100~
What language you working in?
if its any C style language you can simply do 'IX86' wherever you would out it's int value. But if its in other languges you have to convert it: 0x49583836

[option]

Damn andy, you weren't kidding:



Took forever haha

Yeah Hdx I am working in VC++, so the point is, I could just put IX86 into a DWORD, as is, without reversing it, and then send the packet?

[Barabajagal]

The values 'IX86', 1230518326, and 0x49583836 are all equal. They're identical. There is no distinction between them.

[option]

Oh man that's sweet to know.

Alright, now I need a C++ packet buffer so I can pick apart and learn how it works, can't create one myself at the moment because of lack of concept knowledge, all tutorials I've found through search are down (domains), and there seems to be like 4354354 C# ones, but no C++ ones.



PS even though  these questions are rather newb, at least I'm giving you something to do

[Spht]

Damn andy, you weren't kidding:

Wow, what is this the 1800's?  most operating systems have a built-in calculator

[option]

hahah yeahhh well I just learned a lot about bytes, words, dwords, binary, hex, and just wanted to make sure I could actually do the conversion, so instead of just calculating it I tested my knowledge at the same time haha

[Yegg]

hahah yeahhh well I just learned a lot about bytes, words, dwords, binary, hex, and just wanted to make sure I could actually do the conversion, so instead of just calculating it I tested my knowledge at the same time haha

At least it's written proof you're serious about learning.

[Sorc.Polgara]

I see summer break has started, and so you have free time now.  I wondered what happen.  You kind of disappeared, I thought maybe BotDev sacred you away, heh.  Btw, the link in your sig is broken.

[option]

It will most definitely be updated soon, it's at another host at the time being.

And yes I am back, school takes up a good amount of time, but i finished a few more programming courses and am armed with even more knowledge now so I am looking forward to getting back in the swing of things here!