let's say you have a triangle. ABC (corners)
you are given the mesurements of two sides.
Sides AB and BC.
you are also given the angle of B.
You have to find the other side.
b=CA
do you use b² = a²+c²-2ac COS B ?
using the law of cosinus? ( im canadian, no idea on the english conversion of terms)
anyways, had this in class, simple revision but i couldn't find it anywhere in my old notes from previous years, if you could remind me of how do find the CA side, that'd be great..(i think i might have it...)
Yes, what you said is correct.
AC^2 = AB^2 + BC^2 - 2*AB*BC*cos(<ABC)
ah perfect! Is this the right forum to be asking these types of questions? or are they not advanced enough. i beleive i lost my math notes, so i might need more help in the near future :-\
Quote from: Zerg on November 29, 2003, 04:10 PM
ah perfect! Is this the right forum to be asking these types of questions? or are they not advanced enough. i beleive i lost my math notes, so i might need more help in the near future :-\
Yes, there's nothing in the forum rules that discriminates basic math against advanced math.