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Member Forums => Yoni's Math Forum => Topic started by: Probe on May 15, 2006, 04:21 PM

Title: exponent question
Post by: Probe on May 15, 2006, 04:21 PM
can 5^sqrt(3) be solved without a calculator?
Title: Re: exponent question
Post by: rabbit on May 15, 2006, 07:18 PM
Yes.
Title: Re: exponent question
Post by: Probe on May 15, 2006, 07:34 PM
how would you go about doing that?
Title: Re: exponent question
Post by: shout on May 16, 2006, 02:58 AM
5√3 is quite exact. If you go into decimals you will be getting inaccurate answers.
Title: Re: exponent question
Post by: rabbit on May 16, 2006, 06:45 AM
You can still get an approximate solution.
Title: Re: exponent question
Post by: Yoni on May 17, 2006, 07:27 AM
I suppose you could develop the Taylor series for 5^sqrt(x) and calculate its value at x = 3.

You could also think of a few other approximation tricks.
For example, we know that 5^sqrt(3) = sqrt3_root(125).
Maybe you have some approximation of sqrt3_root. (I doubt it's easier than what I said above though.)

The most obvious is that it's between 5 and 5^2 = 25.

It's also between 5^1.7 and 5^1.8, but I don't know how to calculate those.

You could combine two taylor series. Calculate x = sqrt(3) and then calculate 5^x @ that x. I don't think the second calculation would be easy though.

Just some ideas.
Title: Re: exponent question
Post by: rabbit on May 17, 2006, 09:26 AM
1.7 = 1 + 1/7
51 + 1/7 = (51)(51/7)
51/7 is about 1.26, so 5 * 1.26 = 6.3

1.7 = 1 + 1/8
51 + 1/8 = (51)(51/8)
51/8 is about 1.22, so 5 * 1.22 = 6.1

6.1 + 6.3 = 12.4
12.4 / 2 = 6.2
Thus your answer is about 6.2
Title: Re: exponent question
Post by: dxoigmn on May 17, 2006, 12:08 PM
Quote from: rabbit on May 17, 2006, 09:26 AM
1.7 = 1 + 1/7
51 + 1/7 = (51)(51/7)
51/7 is about 1.26, so 5 * 1.26 = 6.3

1.7 = 1 + 1/8
51 + 1/8 = (51)(51/8)
51/8 is about 1.22, so 5 * 1.22 = 6.1

6.1 + 6.3 = 12.4
12.4 / 2 = 6.2
Thus your answer is about 6.2

5^sqrt(3) = 16.2424508
Title: Re: exponent question
Post by: rabbit on May 17, 2006, 03:04 PM
Well hey, nevermind :P
Title: Re: exponent question
Post by: Probe on May 17, 2006, 08:27 PM
Quote from: Yoni on May 17, 2006, 07:27 AM
I suppose you could develop the Taylor series for 5^sqrt(x) and calculate its value at x = 3.

You could also think of a few other approximation tricks.
For example, we know that 5^sqrt(3) = sqrt3_root(125).
Maybe you have some approximation of sqrt3_root. (I doubt it's easier than what I said above though.)

The most obvious is that it's between 5 and 5^2 = 25.

It's also between 5^1.7 and 5^1.8, but I don't know how to calculate those.

You could combine two taylor series. Calculate x = sqrt(3) and then calculate 5^x @ that x. I don't think the second calculation would be easy though.

Just some ideas.
thanks for the input. could you perhaps explain how you came up with 5^sqrt(3) = sqrt3_root(125)? thanks!
Title: Re: exponent question
Post by: Yoni on May 19, 2006, 05:39 AM
Quote from: rabbit on May 17, 2006, 09:26 AM
1.7 = 1 + 1/7
1.7 = 1 + 1/8
umm ok.

Quote from: Probe on May 17, 2006, 08:27 PM
thanks for the input. could you perhaps explain how you came up with 5^sqrt(3) = sqrt3_root(125)? thanks!
Yes.

sqrt(3) * sqrt(3) = 3
So,
sqrt(3) = 3 / sqrt(3)
And,
5^sqrt(3) = 5^(3 / sqrt(3)) = (5^3) ^ (1 / sqrt(3)) = 125^(1 / sqrt(3)) = sqrt3_root(125)
Title: Re: exponent question
Post by: rabbit on May 19, 2006, 06:58 AM
O shit!  It was early............