can 5^sqrt(3) be solved without a calculator?
Yes.
how would you go about doing that?
5√3 is quite exact. If you go into decimals you will be getting inaccurate answers.
You can still get an approximate solution.
I suppose you could develop the Taylor series for 5^sqrt(x) and calculate its value at x = 3.
You could also think of a few other approximation tricks.
For example, we know that 5^sqrt(3) = sqrt3_root(125).
Maybe you have some approximation of sqrt3_root. (I doubt it's easier than what I said above though.)
The most obvious is that it's between 5 and 5^2 = 25.
It's also between 5^1.7 and 5^1.8, but I don't know how to calculate those.
You could combine two taylor series. Calculate x = sqrt(3) and then calculate 5^x @ that x. I don't think the second calculation would be easy though.
Just some ideas.
1.7 = 1 + 1/7
51 + 1/7 = (51)(51/7)
51/7 is about 1.26, so 5 * 1.26 = 6.3
1.7 = 1 + 1/8
51 + 1/8 = (51)(51/8)
51/8 is about 1.22, so 5 * 1.22 = 6.1
6.1 + 6.3 = 12.4
12.4 / 2 = 6.2
Thus your answer is about 6.2
Quote from: rabbit on May 17, 2006, 09:26 AM
1.7 = 1 + 1/7
51 + 1/7 = (51)(51/7)
51/7 is about 1.26, so 5 * 1.26 = 6.3
1.7 = 1 + 1/8
51 + 1/8 = (51)(51/8)
51/8 is about 1.22, so 5 * 1.22 = 6.1
6.1 + 6.3 = 12.4
12.4 / 2 = 6.2
Thus your answer is about 6.2
5^sqrt(3) = 16.2424508
Well hey, nevermind :P
Quote from: Yoni on May 17, 2006, 07:27 AM
I suppose you could develop the Taylor series for 5^sqrt(x) and calculate its value at x = 3.
You could also think of a few other approximation tricks.
For example, we know that 5^sqrt(3) = sqrt3_root(125).
Maybe you have some approximation of sqrt3_root. (I doubt it's easier than what I said above though.)
The most obvious is that it's between 5 and 5^2 = 25.
It's also between 5^1.7 and 5^1.8, but I don't know how to calculate those.
You could combine two taylor series. Calculate x = sqrt(3) and then calculate 5^x @ that x. I don't think the second calculation would be easy though.
Just some ideas.
thanks for the input. could you perhaps explain how you came up with 5^sqrt(3) = sqrt3_root(125)? thanks!
Quote from: rabbit on May 17, 2006, 09:26 AM
1.7 = 1 + 1/7
1.7 = 1 + 1/8
umm ok.
Quote from: Probe on May 17, 2006, 08:27 PM
thanks for the input. could you perhaps explain how you came up with 5^sqrt(3) = sqrt3_root(125)? thanks!
Yes.
sqrt(3) * sqrt(3) = 3
So,
sqrt(3) = 3 / sqrt(3)
And,
5^sqrt(3) = 5^(3 / sqrt(3)) = (5^3) ^ (1 / sqrt(3)) = 125^(1 / sqrt(3)) = sqrt3_root(125)
O shit! It was early............